16=16x^2-12x

Solution for 16=16x^2-12x equation:

16=16x^2-12x

We move all terms to the left:

16-(16x^2-12x)=0

We get rid of parentheses

-16x^2+12x+16=0

a = -16; b = 12; c = +16;
Δ = b2-4ac
Δ = 122-4·(-16)·16
Δ = 1168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1168}=\sqrt{16*73}=\sqrt{16}*\sqrt{73}=4\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{73}}{2*-16}=\frac{-12-4\sqrt{73}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{73}}{2*-16}=\frac{-12+4\sqrt{73}}{-32}
$